用于检查多级数组中特定数字的javascript代码

Question

最近我正在做一些功课，不得不在只有 javascript 的多级数组中找到 0，所以如果有人需要，我就把这段代码留在这里：)var myArray = [        [2, 0, 10, 100],        [3, 4, 5, 0, 10, 0],        [11, 12, 11, 0, 10, 12, 0, 15, 0, 10, 0]    ]; // ugnjezdeni nizovi     var counter = 0;    console.log(myArray, myArray[0].length, myArray[1].length, myArray[2].length);    var arrayLenght1 = myArray[0].length;    var arrayLenght2 = myArray[1].length;    var arrayLenght3 = myArray[2].length;    console.log(arrayLenght1, arrayLenght2, arrayLenght3);    for (var iterator = 0; iterator <= myArray[0].length; iterator++) {        //   console.log("this is the current value " + iterator); mkay        if (myArray[0][iterator] == 0) {            counter = counter + 1;            console.log("this is the count after a row 1 is passed " + counter);        }    }    for (var iterator = 0; iterator <= myArray[1].length; iterator++) {        if (myArray[1][iterator] == 0) {            counter = counter + 1;            console.log("this is the count after a row 2 is passed " + counter);        }    }    for (var iterator = 0; iterator <= myArray[2].length; iterator++) {        if (myArray[2][iterator] == 0) {            counter = counter + 1;            console.log("this is the count after a row 3 is passed " + counter);        }    }    console.log("this is the final count after all the rows have been checked for 0 = " + counter);实际结果是您在变量的指定行中获得 0 的数量。

Answer 1

如果您只是想计算零的数量，则有更有效的方法可以做到这一点

var myArray = [

    [2, 0, 10, 100],

    [3, 4, 5, 0, 10, 0],

    [11, 12, 11, 0, 10, 12, 0, 15, 0, 10, 0]

];

myArray.map((row, rowNumber) => console.log(`number of zeros in row ${rowNumber}:`, row.filter(element => element === 0).length))

如果你想在所有行中总共有零，你可以这样做

var myArray = [

    [2, 0, 10, 100],

    [3, 4, 5, 0, 10, 0],

    [11, 12, 11, 0, 10, 12, 0, 15, 0, 10, 0]

];

const [row1, row2, row3] = myArray.map((row, rowNumber) => row.filter(element => element === 0).length)

console.log(row1);

console.log(row1+row2);

console.log(row1+row2+row3);