3 回答
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TA贡献1936条经验 获得超6个赞
具有正确选择器的QuerySelectorAll将为您提供检查的值:
注意我从对象数组更改为普通对象
const item = {
"lychee": {"price": 10,"lot": 8},
"orange": {"price": 12,"lot": 6},
"apple": {"price": 8, "lot": 3},
"mango": {"price": 12,"lot": 5},
"banana": {"price": 4, "lot": 1}
};
let res = [...document.querySelectorAll("[name=fruits]:checked")]
.map(chk => `${chk.value},lot:${item[chk.value].lot}, price:${item[chk.value].price}`);
document.getElementById("res").innerHTML = res.join("<br/>");
<input type="checkbox" name="fruits" value="lychee" checked> lychee <br />
<input type="checkbox" name="fruits" value="orange"> orange <br />
<input type="checkbox" name="fruits" value="banana" checked> banana <br />
<br/>
<span id="res"></span>
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TA贡献1876条经验 获得超7个赞
您可以使用document.querySelectorAll(".fruits:checked")class 获取所有已检查的元素.fruits。Set用它的值创建一个对象。
使用filter的过滤器item阵列。
var checked = new Set(Array.from(document.querySelectorAll(".fruits:checked")).map(o => o.value));
const item = [{"lychee":{"price":10,"lot":8}},{"orange":{"price":12,"lot":6}},{"apple":{"price":8,"lot":3}},{"mango":{"price":12,"lot":5}},{"banana":{"price":4,"lot":1}}];
let result = item.filter(o => checked.has(Object.keys(o)[0]));
console.log(result);
<input class="fruits" type="checkbox" name="fruits" value="lychee" checked> lychee <br />
<input class="fruits" type="checkbox" name="fruits" value="orange"> orange <br />
<input class="fruits" type="checkbox" name="fruits" value="banana" checked> banana <br />
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TA贡献1818条经验 获得超8个赞
使用过滤器获取选中的值。
然后映射数组并只取每个对象元素的值。
var checked = [...inputElements].filter(inputElement => inputElement.checked);
var valuesOfChecked = checked.map(item => [Object.values(item)[0].price,Object.values(item)[0].lot])
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