替换列表中的单词并附加到同一列表中

Question

我的列表：city=['Venango Municiplaity', 'Waterford ship','New York']预期结果：city = ['Venango Municiplaity ', 'Waterford ship','New York','Venango','Waterford']常用的词：common_words = ['ship','municipality']扫描我的列表中的所有项目，去掉常用词并重新插入到同一个列表中，如预期结果所示。我能够搜索包含常用词的项目，但不确定如何将其替换为空白并重新插入“我的列表”中。到目前为止我的代码：for item in city:    if(any(x in s.lower() for s in item.split(' ') for x in common_words)) :

Answer 1

我建议您使用以下解决方案，使用re.subwithflags=re.IGNORECASE去除忽略大小写的常用词：

import re

city = ['Venango Municipality', 'Waterford ship','New York']

common_words = ['ship','municipality']

toAppend = []

for c in city:

    for cw in common_words:

        if cw.lower() in c.lower().split():

            toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())

city += toAppend

print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']

这是一个使用列表理解的单线样式解决方案，虽然简短，但可读性较差：

import re

city = ['Venango Municipality', 'Waterford ship','New York']

common_words = ['ship','municipality']

city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]

print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']

Answer 2

您可以尝试一下，创建新列表以保存数据，应将数据添加到原始列表中，然后合并结果：

In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']

In [2]: common_words = ['ship', 'municiplaity']

In [3]: list_add = []

In [4]: for item in city:

   ...:     item_words = [s.lower() for s in item.split(' ')]

   ...:     if set(common_words) & set(item_words):

   ...:         new_item = [s for s in item.split(' ') if s.lower() not in common_words]

   ...:         list_add.append(" ".join(new_item))

   ...:         

In [5]: city + list_add

Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']