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从SOAP / JSON提取值

从SOAP / JSON提取值

PHP
Smart猫小萌 2021-05-06 13:16:45
我有一个JSON响应,并且我尝试了多种方法来提取具有(APPROVED)的值,但是这很困难这是回应:PHP,JSON2028000NGNDepositSecure3D{"lkpTransactionId":"1100037249","lkpErrorNo":"0","lkpErrorDescription":"Approved","lkpEnrolled":"Y","lkpEciFlag":"02","authSend":"Y","authErrorNo":"0","authErrorDescription":"Approved","authCavv":"jHyn+7YFi1EUAREAAAAvNUe6Hv8=","authXid":"O0KGgwbJpRpdB8cw4OUfee34PkA=","authEciFlag":"02","authPAResStatus":"Y"}Successful64086914117475714319752028000052019545301******41541100037249MASTERCARDSamuel Adah00SuccessfultrueSUCCESSFULPAYMENT我想以数组或字符串形式获取每个结果。感谢你们。更新:我能够听从您的建议,结果如下:array(12) {  ["lkpTransactionId"]=>  string(10) "1100037249"  ["lkpErrorNo"]=>  string(1) "0"  ["lkpErrorDescription"]=>  string(8) "Approved"  ["lkpEnrolled"]=>  string(1) "Y"  ["lkpEciFlag"]=>  string(2) "02"  ["authSend"]=>  string(1) "Y"  ["authErrorNo"]=>  string(1) "0"  ["authErrorDescription"]=>  string(8) "Approved"  ["authCavv"]=>  string(28) "jHyn+7YFi1EUAREAAAAvNUe6Hv8="  ["authXid"]=>  string(28) "O0KGgwbJpRpdB8cw4OUfee34PkA="  ["authEciFlag"]=>  string(2) "02"  ["authPAResStatus"]=>  string(1) "Y"} 对我来说,获取authErrorDescription的价值真的很困难。我尝试了这个:foreach($res as $user){       echo $user[8]['authErrorDescription'].'<br/>';      //echo $user[0]->authErrorDescription;   }但是结果没有正确显示。
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忽然笑

TA贡献1806条经验 获得超5个赞

在您的示例中,这不是json。杰森(Json)以{


您可以使用此代码将json转换为php Array


$res = json_decode('{"lkpTransactionId":"1100037249","lkpErrorNo":"0","lkpErrorDescription":"Approved","lkpEnrolled":"Y","lkpEciFlag":"02","authSend":"Y","authErrorNo":"0","authErrorDescription":"Approved","authCavv":"jHyn+7YFi1EUAREAAAAvNUe6Hv8=","authXid":"O0KGgwbJpRpdB8cw4OUfee34PkA=","authEciFlag":"02","authPAResStatus":"Y"}',true);


var_dump($res);

如果您有响应(出于任何原因),则必须在使用json_decode之前解析此字符串。

strpos($str,'{')-将返回字符串中“ {”的位置

substr-将返回所需的字符串部分。


最终,您应该像这样:


$res = json_decode(substr($yourString,strpos($yourString,'{'),strpos($yourString,'}') - strpos($yourString,'{')+1),true);



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反对 回复 2021-05-28
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