POST请求空白，为什么？

Question

我将以下代码另存为send.php：<?php$to_email = "[e-mail]";$subject = $_POST['subject'];$body = "Hi, This is test email send by PHP Script";$headers = "From: [e-mail]";if ( mail($to_email, $subject, $body, $headers)) {    echo("Email successfully sent to $to_email...");} else {    echo("Email sending failed...");}?>如果我导航到https://myWebsite.com/Stuff/send.php 并发送电子邮件，该电子邮件将发送$subject = "something"但是如果我设置$subject为POST变量。当我在浏览器中写入此URL时，它不会发送主题（例如，电子邮件仍然发送，但主题现在为空）： https://myWebsite.com/Stuff/send.php?subject=notworking

Answer 1

要获得两者$_POST ，$_GET您可以使用$_REQUEST适用于两者的东西。

在您的代码中替换

$subject = $_GET['subject'];

和

$subject = $_REQUEST['subject'];

如果有人直接在浏览器中直接点击了网址，但没有设置主题，则可以阻止他们使用

if(!empty($_REQUEST['subject']))

{

  $to_email = "[e-mail]";

  $subject = $_REQUEST['subject'];

  $body = "Hi, This is test email send by PHP Script";

  $headers = "From: [e-mail]";

  if ( mail($to_email, $subject, $body, $headers))

    echo("Email successfully sent to $to_email...");

  else

    echo("Email sending failed...");

}

Answer 2

尝试一下。

 <?php

    $to_email = "[e-mail]";

    $subject = (isset($_GET['subject']) && (!empty($_GET['subject']))?$_GET['subject']:"No Subject";

    $body = "Hi, This is test email send by PHP Script";

    $headers = "From: [e-mail]";

    if ( mail($to_email, $subject, $body, $headers))

        echo("Email successfully sent to $to_email...");

    else

        echo("Email sending failed...");

?>

Answer 3

如果您要从网址参数中提取值，则需要使用$_GET 全局变量来获取这样的数据，

<?php

$to_email = "[e-mail]";

$subject = $_GET['subject'];

$body = "Hi, This is test email send by PHP Script";

$headers = "From: [e-mail]";

if ( mail($to_email, $subject, $body, $headers)) {

    echo("Email successfully sent to $to_email...");

} else {

    echo("Email sending failed...");

}

?>