我将如何通过与另一个MySQL数组进行比较来更改它？

Question

我想显示通过json数据集（来自表“ score”）来自数据库的分数，效果很好，但是我的quiz_id是外键，这意味着数据集将包含ID，而不是名称测验。在CanvasJS图表上看起来不太好。quiz_name位于测验表中，主键为quiz_id。我将如何使json数据集包含quiz_name而不是quiz_id？我的test.php，它正在创建json：<?phpheader('Content-Type: application/json');$con = mysqli_connect("123.123.123.123", "Seba0702", "", "kayeetdb");    $data_points = array();    $result = mysqli_query($con, "SELECT * FROM score");    while($row = mysqli_fetch_array($result))    {               $point = array("label" => $row['quiz_id'] , "y" => $row['quiz_score']);       array_push($data_points, $point);            }    echo json_encode($data_points, JSON_NUMERIC_CHECK);mysqli_close($con);?>我的表格：测验表：得分表：我希望json包含quiz_name和quiz_score。

Answer 1

要从另一个表中检索信息，您需要一个联接

SELECT score.quiz_id, score.student_id, score.quiz_score, quiz.name

FROM score

INNER JOIN quiz on quiz.quiz_id = score.quiz_id