我应该在这里使用哪种算法？在字符串数组中查找字符串

Question

我有2个数组。一个Array有字符串，我在找。static String[] namesToLookFor = { "NR", "STAFFELNR", "VONDATUM"};另一个Array有字符串，我是从* .csv文件中获得的。indexString = indexReader.readLine();indexArray = indexString.split(";");我的目标是实现system.out.println() ，indexArray[]而不是的价值观namesToLookFor[]。例如：namesToLookFor = {"NR"};indexArray = {"HELLO","NR"};//Any Algorithm here...因此，在这种情况下"HELLO"应将其打印出来，因为它不在namesToLookFor[]数组中。

Answer 1

您可以遍历indexArray并检查每个元素是否包含在namesToLookFor数组中：

    String[] namesToLookFor = {"NR"};

    String[] indexArray = {"HELLO","NR"};

    List<String> excludedNames = Arrays.asList(namesToLookFor);

    for(String s : indexArray) {

        if (!excludedNames.contains(s)) {

            System.out.println(s);

        }

    }

将仅输出“ HELLO”。

Answer 2

如果您使用的是Java8，则可以执行以下操作

List<String> list = Arrays.asList(namesToLookFor);

Arrays.stream(indexArray)

        .filter(item -> !list.contains(item))

        .forEach(System.out::println);

Answer 3

// Put array into set for better performance

Set<String> namesToFilter = new HashSet<>(Arrays.asList("NR", "STAFFELNR"));

String[] indexArray = indexReader.readLine().split(";");

// Create list with unfiltered values and remove unwanted ones

List<String> resultList = new ArrayList<>(indexArray);

resultList.removeAll(namesToFilter);

// Do with result whatever you want

for (String s : resultList)

    System.out.println(s);