我有一个TXT文件,格式为22px 3111px 32618px 813px 4122px 4311px 291其中第一列是字体大小(“ px”),第二列是字符计数。是否有任何方法可以汇总(总和)所有字体大小(键)上的字符数(值),然后使用python字典除以总字符数?假定的解决方案应采用以下形式:11px 83% # =(326+291)/(31+326+8+41+43+291)13px 6%18px 1%22px 10%
1 回答
郎朗坤
TA贡献1921条经验 获得超9个赞
无需打扰熊猫。文本文件是可迭代的。只需打开它,在行(字符串)上操作并填写字典即可。
file = "font.txt"
with open(file, "r") as f:
dic = dict()
for line in f:
x = line.strip("\n").split(" ")
key = int(x[0].strip("px"))
value = int(x[1])
if key not in dic.keys():
dic[key] = [value]
else:
dic[key].append(value)
输出:
{22: [31, 43], 11: [326, 291], 18: [8], 13: [41]}
然后是简单的数学运算:
total_number_of_character = sum([sum(x) for x in dic.values()])
percentage = percentage = {key:sum(value)/total_number_of_character*100 for (key, value) in dic.items()}
输出:
{22: 10.0,
11: 83.37837837837839,
18: 1.0810810810810811,
13: 5.540540540540541}
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