我正在尝试获取所有用户(除外request.user),并按他们收到的最后一条消息的日期时间对其进行排序。也许我做错了。@login_requireddef get_users(request): if request.method == 'POST': users = list(User.objects.filter(~Q(username = request.user)) .order_by('personal_messages__sent_date').values()) return HttpResponse(dumps({'users': users})) return redirect('message:index')dumps来自json_tricks。Vue.js对象通过JS fetchMy models.py接收数据from django.db import modelsfrom django.conf import settings class PersonalMessage(models.Model): text = models.TextField() sender = models.ForeignKey(settings.AUTH_USER_MODEL, related_name='personal_messages', null=True, on_delete=models.SET_NULL) recipient = models.ForeignKey(settings.AUTH_USER_MODEL, null=True, on_delete=models.SET_NULL) sent_date = models.DateTimeField('sent date', auto_now_add=True)问题是,如果我只做得users = list(User.objects.filter(~Q(username = request.user)).values())很好,但是如果我添加order_by,users = list(User.objects.filter(~Q(username = request.user)) .order_by('personal_messages__sent_date').values())我将为每个用户获得重复项。如果用户与n条消息链接,似乎它会向每个用户返回n次。也许还有另一种方式。任何想法?
1 回答

临摹微笑
TA贡献1982条经验 获得超2个赞
您需要使用聚合,查询如下所示:
User.objects.filter(
~Q(username = request.user)
).annotate(
last_message_sent_date=Max('personal_messages__sent_date')
).order_by(
'last_message_sent_date'
)
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