将Java解密代码迁移到Golang

Question

在过去的几天里，我一直在努力将Java代码迁移到Golang，现在我陷入了困境。这是有效的Java代码：final Key k = new SecretKeySpec(keyString.getBytes(), "AES");Cipher c = Cipher.getInstance("AES");c.init(Cipher.DECRYPT_MODE, k);final InputStream in = new BufferedInputStream(new FileInputStream(fileNameToDecrypt));final CipherInputStream instream = new CipherInputStream(in, c);if (instream.read() != 'B') {    System.out.println("Error");}if (instream.read() != 'Z') {    System.out.println("Error");}final CBZip2InputStream zip = new CBZip2InputStream(instream);我在Golang中的实现：c, _ := aes.NewCipher([]byte(keyString))// IV must be defined in golangiv := []byte{0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,             0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00}d := cipher.NewCBCDecrypter(c, iv)fi, _ := os.Open(fileNameToDecrypt)stat, _ := fi.Stat()enc := make([]byte, stat.Size())dec := make([]byte, stat.Size())fi.Read(enc)d.CryptBlocks(dec, enc)instream := bytes.NewBuffer(dec)zip := bzip2.NewReader(instream)到目前为止我所知道的：这段代码中所有被忽略的错误值_都nil在这段代码中必须为省略bzip2标头（“ BZ”）CBzip2InputStream，但不能为bzip2.NewReader从instreamJava和golang中读取的前16个字节是相同的，从第17个字节开始，所有字节由于某种原因而有所不同