如何在struct方法中设置和获取字段

Question

创建像这样的结构后：type Foo struct {    name string}func (f Foo) SetName(name string) {    f.name = name}func (f Foo) GetName() string {    return f.name}如何创建Foo的新实例并设置并获取名称？我尝试了以下方法：p := new(Foo)p.SetName("Abc")name := p.GetName()fmt.Println(name)没有打印任何内容，因为名称为空。那么如何设置结构中的字段？https://play.golang.org/p/_xkIc-n6Wbk

Answer 1

评论（和工作）示例：

package main

import "fmt"

type Foo struct {

    name string

}

// SetName receives a pointer to Foo so it can modify it.

func (f *Foo) SetName(name string) {

    f.name = name

}

// Name receives a copy of Foo since it doesn't need to modify it.

func (f Foo) Name() string {

    return f.name

}

func main() {

    // Notice the Foo{}. The new(Foo) was just a syntactic sugar for &Foo{}

    // and we don't need a pointer to the Foo, so I replaced it.

    // Not relevant to the problem, though.

    p := Foo{}

    p.SetName("Abc")

    name := p.Name()

    fmt.Println(name)

}

测试它并进行Go之旅，以全面了解有关方法和指针以及Go的基础知识。