根据另一个对象数组中的过滤条件来过滤对象数组：JavaScript

Question

我希望myArray根据中提到的条件进行过滤myFilter。myFilter的键已定义，可以使用进行访问myFilter.field，myFilter.value其中as的key：valuemyArray未知。我们可能必须遍历每个对象，myArray才能首先将myArray [key]与匹配myFilter.field，然后再将myArray [key]与myFilter.value进行匹配。那应该是AND逻辑myArray = [{    make: "Honda",    model: "CRV",    year: "2017"  },  {    make: "Toyota",    model: "Camry",    year: "2020"  },  {    make: "Chevy",    model: "Camaro",    year: "2020"  }]myFilter = [{    field: "make",    value: "Chevy",    type: "string"  },  {    field: "year",    value: "2020",    type: "date"  }];// Expected OutPut:myArray = [{  make: "Chevy",  model: "Camaro",  year: "2020"}]var tempArray = [];const keysToMatch = myFilter.length;let matchedItems = [];myArray.forEach((data) => {  matchedItems = [];  let itemsToFind = Object.values(data);  myFilter.forEach((filterItem) => {    if (itemsToFind.indexOf(filterItem.value) != -1) {      matchedItems.push("matched");    }  });  //check if everything matched  if (matchedItems.length === keysToMatch) {    tempArray.push(data);  }});console.log(tempArray);

Answer 1

var tempArray = [];

const keysToMatch = myFilter.length;

let matchedItems = [];

myArray.forEach((data) => {

    matchedItems = [];

    let itemsToFind = Object.values(data);

    myFilter.forEach((filterItem) => {

        if (itemsToFind.indexOf(filterItem.value) != -1) {

            matchedItems.push("matched");

        }

    });

    //check if everything matched

    if (matchedItems.length === keysToMatch) {

        tempArray.push(data);

    }

});

console.log(tempArray);