如何获得动态微调器选择的数组中的项目ID？

Question

我完美地创建了动态微调器，如下所示        k++;        flag=k;        final LinearLayout.LayoutParams lparams = new         LinearLayout.LayoutParams(380,120);        lparams.setMargins(1, 20, 1, 0);        colorSpinner[flag] = new Spinner(getActivity());        colorSpinner[flag].setLayoutParams(lparams);        colorSpinner[flag].setId(flag);        colorSpinner[flag].setAdapter(new ArrayAdapter<String>(getContext(), android.R.layout.simple_spinner_dropdown_item, color_list));        loadColorSpinnerData(URL);        colorSpinner[flag].setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {            @Override            public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l)            {                color_id = datalist1.get(i).getId();            }            @Override            public void onNothingSelected(AdapterView<?> adapterView) {                // DO Nothing here            }        });mLayout.addView(colorSpinner[flag]);color_array.add(colorSpinner[flag]);如何获取数组中的颜色ID这是行不通的String[] Acolorid = new String[color_array.size()];    for(int i = 0; i < color_array.size(); i++){        Acolorid[i] = String.valueOf(color_array.get(i).getSelectedItemPosition()+1); //Acolorid[j]= String.valueOf(color_id);//color_array.get(i).getSelectedItem().toString();        Hcolorid=String.join(",",Acolorid);    }请给我我想获取数组中的颜色ID而不获取项目位置的解决方案。

Answer 1

一种方法是使用View.setTag（）存储以后要检索的数据。就像是 ：

     public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l)

        {

            // get some data related to the selected item

            color_id = datalist1.get(i).getId();

            // attach it to the spinner

            adapterView.setTag(color_id);

        }

        @Override

        public void onNothingSelected(AdapterView<?> adapterView) {

            // DO Nothing here

        }

稍后检索：

String[] Acolorid = new String[color_array.size()];

    for(int i = 0; i < color_array.size(); i++){

        // get the saved data

        Object data = color_array.get(i).getTag();

        if (data != null) {

            Acolorid[i] = data.toString();

        }

    }

    Hcolorid=String.join(",",Acolorid);