我想从$ employee_salary数组中的$ employee数组中添加薪水键

Question

我想从$ employee_salary数组中的$ employee数组中添加薪水关键字，这两个数组都是关联的，并且salary仅根据索引添加到薪水。存在一些未定义偏移量的错误。我无法识别问题。这些错误就像未定义的偏移量一样，这会是什么问题？    $employee = array(0=>    array("employee_id"=>1, "firstName"=>"Zahir", "lastName"=>"Alam", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"        ,"Head"=>            array("Id"=>3 , "Name"=>"Sourasis Roy")    ),1=>    array("employee_id"=>2, "firstName"=>"Amith", "lastName"=>"Manniken", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"        ,"Head"=>            array("Id"=>3 , "Name"=>"Sourasis Roy")    ),2=>    array("employee_id"=>3, "firstName"=>"Sourasis", "lastName"=>"Roy", "Age"=>28, "Company"=>"Switchme", "Role"=>"CTO"),3=>    array("employee_id"=>4, "firstName"=>"Aditya", "lastName"=>"Mishra", "Age"=>29, "Company"=>"Switchme", "Department"=>"Tech", "Role"=>"CEO"),4=>    array("employee_id"=>5, "firstName"=>"Priti", "lastName"=>"Lata", "Age"=>24, "Company"=>"Switchme", "Role"=>"HR"),5=>    array("employee_id"=>6, "firstName"=>"Sumita", "lastName"=>"Nath", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm"),6=>    array("employee_id"=>7, "firstName"=>"Tarini", "lastName"=>"Khanna", "Age"=>22, "Company"=>"Switchme", "Role"=>"Content Writer"),7=>    array("employee_id"=>8, "firstName"=>"Abhisek", "lastName"=>"Soni", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm","Head"=>array("Id"=>5 , "Name"=>"Sumita Nath")    ),8=>    array("employee_id"=>9, "firstName"=>"Ankit", "lastName"=>"Pump", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm"        ,"Head"=>            array("Id"=>5 , "Name"=>"Sumita Nath")    ),9=>    array("employee_id"=>10, "firstName"=>"Pogo", "lastName"=>"Laal", "Age"=>23, "Company"=>"Switchme", "Role"=>"Designer"),10=>    array("employee_id"=>11, "firstName"=>"Sabina", "lastName"=>"Sekh", "Age"=>28, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm"),

Answer 1

如果您可以注意到，两者$employee[$j]和$employee_salary[$j]都是数组，那么您不应该等同于它们之间的比较。另外，$employee和$employee_salary数组的大小都不相同，这就是为什么在循环中遇到未定义的索引错误的原因。$employee_salary[$j]for

将嵌套foreach循环与引用一起使用以实现所需的结果，如下所示：

foreach($employee as &$emp1){

    foreach($employee_salary as $emp2){

        if($emp1['employee_id'] == $emp2['employee_id']){

            $emp1['salary'] = $emp2['salary'];

        }

    }

}

// Display complete array structure of $employee

var_dump($employee);

Answer 2

您可以简单地使用 array_walk

$emp_s = array_column($employee_salary, 'salary','employee_id');

array_walk($employee, function(&$v, $k) use ($emp_s){

  if(array_key_exists($k, $emp_s)){

    $v['salary'] = $emp_s[$k];

  }

});

或者

$temp        = array_column($employee_salary, 'salary','employee_id');

array_walk($employee, function(&$v, $k) use ($temp){

    $v['salary'] = array_key_exists($k, $temp) ? $temp[$k] : null;

});