PHP 7 Mime和PDF验证

Question

这在PHP 5中有效，但是现在不行了：if (function_exists('finfo_open')) {  $mime = finfo_open(FILEINFO_MIME_TYPE);  $mime_type = finfo_file($mime, "FILE-PATH");  if($mime_type == array("application/pdf", "image/jpeg", "image/png"))    echo "file is pdf";  else    echo "file is not pdf";  finfo_close($mime);}

Answer 1

您将字符串与数组进行了比较，这是正确的代码：

if (function_exists('finfo_open')) {

  $mime = finfo_open(FILEINFO_MIME_TYPE);

  if (in_array(finfo_file($mime, 'FILE-PATH'), array('application/pdf', 'image/jpeg', 'image/png')))

    echo 'file is pdf';

  else

    echo 'file is not pdf';

  finfo_close($mime);

}