我有XML格式<POS> <Source PseudoCCode="BOA" ISOCountry="US" AgentDutyCode="J114N"> <RequestorID Type="11" ID="T921"> <CompanyName Code="CP" CodeContext="123T"/> </RequestorID> </Source> <Source> <RequestorID Type="1" ID="34778"/> </Source> <Source> <RequestorID Type="9" ID="ZF"/> </Source> <Source> <RequestorID Type="17" ID="mabaan"/> </Source></POS>`我有一个要反序列化的php对象。 class POS { /** * @ORM\OneToMany(targetEntity="POS_Source", mappedBy="POS", orphanRemoval=true) * @Groups("Include") */private $Source;public function __construct(){ $this->Source = new ArrayCollection();}/** * @return ArrayCollection|OTA_POS_Source[] */public function getSource(): ArrayCollection{ return $this->Source;}public function addSource(POS_Source $source): self{ if (!$this->Source->contains($source)) { $this->Source[] = $source; $source->setPOS($this); } return $this;}public function removeSource(POS_Source $source): self{ if ($this->Source->contains($source)) { $this->Source->removeElement($source); // set the owning side to null (unless already changed) if ($source->getPOS() === $this) { $source->setPOS(null); } } return $this;}它给了我POS对象，而不是给它一个下面的数组，而不是POS_Source对象的集合。 POS {#839 ▼ -id: null -Source: array:5 [▼ 0 => array:4 [▶] 1 => array:1 [▶] 2 => array:1 [▶] 3 => array:1 [▶] 4 => array:1 [▶] ] }我如何才能使这项工作一直填充到对象树的底部。当我从对象结构序列化为XML时，它的效果很好。
3 回答
largeQ
TA贡献2039条经验 获得超7个赞
下面是一个最小的工作例如反序列化XML到单个POS实例与ArrayCollection的POS_Source实例。我扔掉了对反序列化此特定XML而言不是必不可少的所有规范化器等。
use Doctrine\Common\Collections\ArrayCollection;
use Symfony\Component\Serializer\Encoder\XmlEncoder;
use Symfony\Component\Serializer\Normalizer\ArrayDenormalizer;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
use Symfony\Component\Serializer\Serializer;
use Symfony\Component\PropertyInfo\Extractor\ReflectionExtractor;
class POS
{
// ... just as in the question ...
}
/**
* Minimal implementation of POS_Source for purposes of this deserialization example.
*/
class POS_Source
{
private $RequestorID;
public function setPOS(POS $POS)
{
}
public function getRequestorID()
{
return $this->RequestorID;
}
public function setRequestorID($RequestorID)
{
$this->RequestorID = $RequestorID;
}
}
$data = '<POS>
<!-- ... the same XML as in the question ... -->
</POS>';
$normalizers = [
new ArrayDenormalizer(),
new ObjectNormalizer(null, null, null, new ReflectionExtractor())
];
$encoders = [new XmlEncoder()];
$serializer = new Serializer($normalizers, $encoders);
$pos = $serializer->deserialize($data,POS::class,'xml');
dump($pos);
印刷：
POS {#14
-Source: Doctrine\Common\Collections\ArrayCollection {#11
-elements: array:4 [
0 => POS_Source {#17
-RequestorID: array:3 [
"@Type" => 11
"@ID" => "T921"
"CompanyName" => array:3 [
"@Code" => "CP"
"@CodeContext" => "123T"
"#" => ""
]
]
}
1 => POS_Source {#27
-RequestorID: array:3 [
"@Type" => 1
"@ID" => 34778
"#" => ""
]
}
2 => POS_Source {#22
-RequestorID: array:3 [
"@Type" => 9
"@ID" => "ZF"
"#" => ""
]
}
3 => POS_Source {#25
-RequestorID: array:3 [
"@Type" => 17
"@ID" => "mabaan"
"#" => ""
]
}
]
}
}
POPMUISE
TA贡献1765条经验 获得超5个赞
这是部分答案，而不是解决方案。
因此，看起来反序列化不支持嵌入式php对象，并且您已经创建了一个自定义反序列化方法。
我仍在使用解决方案，但简短的答案是您必须遍历标准化数组，然后尝试匹配属性名称。我正在尝试寻找一种方法来查询对象，以仅查询序列化组文档块批注中包含的那些属性。
宝慕林4294392
TA贡献2021条经验 获得超8个赞
在反序列化包含其他对象的对象时，必须提供ObjectNormalizer一个类型提取器来确定嵌套对象的类型。
use Symfony\Component\PropertyInfo\Extractor\ReflectionExtractor;
// ...
$normalizers = [
new DateTimeNormalizer(),
new ArrayDenormalizer(),
new PropertyNormalizer(),
new ObjectNormalizer($classMetadataFactory, $metadataAwareNameConverter, null, new ReflectionExtractor()), // added type extractor as fourth argument
];
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