如何删除重复项并在ViewSettingsItem中仅显示唯一值？

Question

我正在从后端获取JSON数组中的重复值，并且我想删除重复值并仅在SAPUI5 ViewSettingsItem中显示唯一值。请帮助我。{"d": {    "results": [{               "Status": "Completed",        "sId": "C1"    },     {               "Status": "Completed",        "sId": "C1"    },    {               "Status": "Started",        "sId": "S1"    },    {               "Status": "In Process",        "sId": "P1"    },{             "Status": "Completed",        "sId": "C1"    }]}}XML视图：<core:FragmentDefinition xmlns="sap.m" xmlns:core="sap.ui.core">    <ViewSettingsDialog >        <filterItems>            <ViewSettingsFilterItem>                <items>                    <ViewSettingsItem text="{Status}" key="{sId}"/>                </items>             </ViewSettingsFilterItem>        </filterItems>    </ViewSettingsDialog></core:FragmentDefinition>

Answer 1

您可以使用reduce和anObject来跟踪先前添加的内容sId's

let obj = {"d": {"results": [{"Status": "Completed","sId": "C1"}, {"Status": "Completed","sId": "C1"},{"Status": "Started","sId": "S1"},{"Status": "In Process","sId": "P1"},{"Status": "Completed","sId": "C1"}]}}

let track = {}

let results = obj.d.results.reduce((op,inp)=>{

  if(!track[inp.sId]){

    op.push(inp)

    track[inp.sId] = inp

  }

  return op

},[])

let op = {d:{results:results}}

console.log(op)