Spring Data Cassandra：InvalidQueryException：UUID

Question

实体@Builder@Getter @Setter@ToString(doNotUseGetters = true)@EqualsAndHashCode(doNotUseGetters = true)@Table(value = "entity")public class Entity implements Serializable {    @PrimaryKeyColumn(name = "id", ordinal = 0, type = PrimaryKeyType.PARTITIONED)    @CassandraType(type = DataType.Name.UUID)    private UUID Id;    @Column("list_name")    @CassandraType(type = DataType.Name.TEXT)    private String name;    @Column("type")    @CassandraType(type = DataType.Name.TINYINT)    private Byte type;实体回购@Repositorypublic interface EntityRepo extends BaseRepo<Entity, UUID> {    @Query("SELECT * FROM entity WHERE id IN (:id)")    Collection<ListEntity> findByIds(@Param("id") Collection<UUID> listIds);    @Query("SELECT * FROM entity WHERE list_id = :id")    ListEntity findById(@Param("id") UUID id);}  询问listRepo.findByListId(UUIDs.random())listRepo.findByListIds(Arrays.asList(UUIDs.random())两者都导致CassandraInvalidQueryException/InvalidQueryExceptionorg.springframework.data.cassandra.CassandraInvalidQueryException: Query; CQL [SELECT * FROM lists WHERE list_id IN (?)]; UUID should be 16 or 0 bytes (20); nested exception is com.datastax.driver.core.exceptions.`InvalidQueryException: UUID should be 16 or 0 bytes (20)这里缺少什么吗？有人可以帮忙吗？

Answer 1

运行Spark应用程序时出现相同的错误。

执行Cassandra查询时出现错误，并且在预期为UUID类型的地方，该查询发送了一些其他数据类型。就我而言，它是一个字符串。传递正确的数据类型（UUID代替String）解决了该问题。