JSON：使用php从数组中提取特定行

Question

我正在尝试从我拥有的JSON格式中获取特定数据。我在练习中使用预构建的json。JSON格式是这样的：[{"userId": 1,"id": 1,"title": "sunt aut facere repellat provident occaecati excepturi optio  reprehenderit","body": "quia et suscipit\nsuscipit recusandae consequuntur expedita et cum\nreprehenderit molestiae ut ut quas totam\nnostrum rerum est autem sunt   rem eveniet architecto"},{"userId": 1,"id": 2,"title": "qui est esse","body": "est rerum tempore vitae\nsequi sint nihil reprehenderit dolor beatae ea dolores neque\nfugiat blanditiis voluptate porro vel nihil molestiae ut reiciendis\nqui aperiam non debitis possimus qui neque nisi nulla"},{"userId": 1,"id": 3,"title": "ea molestias quasi exercitationem repellat qui ipsa sit aut","body": "et iusto sed quo iure\nvoluptatem occaecati omnis eligendi aut ad\nvoluptatem doloribus vel accusantium quis pariatur\nmolestiae porro eius odio et labore et velit aut"}] 等等...所以我要做的是从每个对象中获取标题数组。这是我的代码：<?php$url = "https://jsonplaceholder.typicode.com/posts" ;//  Initiate curl$ch = curl_init() ;curl_setopt($ch, CURLOPT_URL, $url);curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($ch) ;curl_close($ch) ;$data = json_decode($result);foreach ($data as $datavalue) {echo $datavalue->title;echo "<br/>" ;}现在，我要显示的是特定对象的标题，比如说user id = 2。我该如何说服。请帮助我的查询。任何帮助，我们真的很感激。

Answer 1

您可以在循环中添加条件以检查想要的行，当找到时，可以将其存储在这样的变量中：

<?php

  $data = json_decode($result);

  $data = json_decode($result);

  $userId = 1;

  $result = null;

  foreach ($data as $datavalue) {

    echo $datavalue->title;

    if ($datavalue->userId == $userId) {

       $result = $datavalue;

       break;

    }

    echo "<br/>" ;

  }

var_dump($result); // if you want to display the title you can simply do $result->title but remember to check if $result is not null

Answer 2

您可以使用以下内容：

$id = 2;

getTitle($data, $id);

function getTitle($data = null, $id = null)

{

    foreach ($data as $datavalue) {

        if ($datavalue->id == $id) {

            echo $datavalue->title;

            echo "<br/>";

        }

    }

}