SQL数组var_dump不显示任何内容

Question

我有一些加载工作时间的代码。我的数据库看起来像id - int(11)day - varchar(255)starttime - (time)endtime - (time)date - (date)type - int(1)我尝试通过以下方式获取数据：if ($conn->connect_error) {    die("Connection failed: " . $conn->connect_error);} echo "Connected successfully";function get_all_records($sql){    global $conn;    $result = $conn->query($sql);    $result = [];    while($row = $result->fetch_assoc()) $result[array_shift($row)] = $row;    return $result;}$sql = "SELECT day, starttime, endtime FROM schedule WHERE type =  ";$shop_hours = array_merge(    get_all_records($sql . "0 ORDER BY id"),    get_all_records($sql . "1 and YEARWEEK('DATE') = '201915'"));var_dump ($shop_hours);?>仅显示内容已成功连接

Answer 1

您正在用一个空数组覆盖结果变量。您应该更改此数组的名称：

$result = [];

Answer 2

我在第14行发现了问题

而（$行= $查询- > FETCH_ASSOC（））$结果[array_shift（$行）] = $行;

    <?php    

$conn = new mysqli($dbhost, $dbusername, $dbpassword, $dbname);

if ($conn->connect_error) {

    die("Connection failed: " . $conn->connect_error);

} 

echo "Connected successfully";

function get_all_records($sql){

  global $conn;

  $query = $conn->query($sql);

  $result = [];

  while($row = $query->fetch_assoc()) $result[array_shift($row)] = $row;

  return $result;

}

$sql = "SELECT day, starttime, endtime FROM schedule WHERE type = ";

$shop_hours = array_merge(

  get_all_records($sql . "0 ORDER BY id"),

  get_all_records($sql . "1 and YEARWEEK('DATE') = '201915'")

);

var_dump($shop_hours);

?>