如何在Java中存储列表中匹配的元素

Question

how to convert ascii value of 49 to actual char in java我的代码在下面，我正在尝试存储不是以前缀a或g开头的列表中的元素 void display(){    String[] inpArray={"apple","orange","grapes"};    LinkedList<String> listOne = new LinkedList<String>(Arrays.asList(inpArray));    LinkedList<String> listTwo = new LinkedList<String>();    listTwo.add("melon");    listTwo.add("apple");    listTwo.add("mango");    String[] result1 = {};    for(String res : listOne){    if(res.startsWith("a")||res.startsWith("g")){        System.out.println("--> "+res);    }else{        System.out.println("** "+res);        //result1 = res;//unable to store in string array or to list        // here i have to add all strings how to do that please help me    }

Answer 1

如果要将元素存储到数组中，可以List先将其放入List数组中，然后通过List.toArray以下方式将其转换为数组：

LinkedList<String> linkedList = new LinkedList<>();

for (String res : listOne) {

    if (res.startsWith("a") || res.startsWith("g")) {

        System.out.println("--> " + res);

    } else {

        System.out.println("** " + res);

        linkedList.add(res);

    }

}

String[] result1 = new String[linkedList.size()];

linkedList.toArray(result1);

Answer 2

Please find the code for storing the element in String array using index i;

package com.test.stackoverflow;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.List;

public class TestClass {

    public static void main(String[] args) {

        // TODO Auto-generated method stub

        display();

    }

    public static void display() {

        String[] inpArray = { "apple", "orange", "grapes" };

        List<String> listOne = new ArrayList<String>(Arrays.asList(inpArray));

        List<String> listTwo = new ArrayList<String>();

        listTwo.add("melon");

        listTwo.add("apple");

        listTwo.add("mango");

        String[] result1 = new String[listOne.size()];

        int i =0;

        for (String res : listOne) {

            if (res.startsWith("a") || res.startsWith("g")) {

                System.out.println("--> " + res);

            } else {

                System.out.println("** " + res);

                result1[i++] = res;

            }

        }

        for(String val : result1){

            System.out.println("Value"+val);

        }

    }

}