获取不断变化的Integer的最新Int 2值

Question

我正在尝试检查一个不断变化的速度整数中的值，我要检查的值是当前值以及它之前的值，我有这段代码，但是由于某些原因它无法正常工作。我的问题是如何有效保存不断变化的Speed整数的最新2个值这是我的代码 int CurrentValue; // The Integer is already defined and initialized, this is the latest value of it int PriorValue; // this value is the one that was prior to the current one CurrentValue = ChangingInt; // here we save the current Speed value in ChangingInt if (CurrentValue != ChangingInt){     PriorValue = CurrentValue; /* replacing the CurrentValue value as the prior one     since it has changed according to the if statement */ }

Answer 1

您可以添加一个temp变量来存储的值CurrentValue。

int CurrentValue;

int PriorValue;

int temp = CurrentValue; //Add a temp variable to store CurrentValue.

CurrentValue = ChangingInt;        

PriorValue = temp;

Answer 2

int ChangingInt = ...          // ChangingInt = A, PriorValue = B, CurrentValue = C

...

int PriorValue = CurrentValue  // ChangingInt = A, PriorValue = C, CurrentValue = C

int CurrentValue = ChangingInt // ChangingInt = A, PriorValue = B, CurrentValue = A

PriorValue在运行之后，我们将不需要，因为我们只需要最后两个值，所以我们应该PriorValue首先将其更改为CurrentValue（因为CurrentValue需要成为new PriorValue），以进行重新分配。然后，我们可以更改CurrentValue为ChangingInt。