我正在使用Excel电子表格来填充字典。然后,我使用这些值将另一个数据帧的值乘以引用,但是尝试时会给我错误。为了避免错误,我决定将excel电子表格制作成字典,但是我没有成功。我这样做是因为字典最终会变长,并且编辑键及其值太繁琐了。我正在使用Python 2.7import pandas as pd#READ EXCEL FILEdf = pd.read_excel("C:/Users/Pedro/Desktop/dataframe.xls")#Store the keys with its value in a dictionary. This will become df2d = {"M1-4":0.60,"M1-5/R10":0.85,"C5-3":0.85,"M1-5/R7-3":0.85,"M1-4/R7A":0.85,"R7A":0.85,"M1-4/R6A":0.85,"M1-4/R6B":0.85,"R6A":0.85,"PARK":0.20,"M1-6/R10":0.85,"R6B":0.85,"R9":0.85,"M1-5/R9":0.85}#Convert the dictionary to an Excel spreadsheetdf5 = pd.DataFrame.from_dict(d, orient='index')df5.to_excel('bob_dict.xlsx')#populatethe dictionary from the excel spreadsheetdf2 = pd.read_excel("C:/Users/Pedro/Desktop/bob_dict.xlsx")#Convert dtframe back to a dictionarydictionary = df2.to_dict(orient='dict')#Pass the dictionary as reference b = df.filter(like ='Value').valuesc = df.filter(like ='ZONE').replace(dictionary).astype(float).valuesdf['pro_cum'] = ((c * b).sum(axis =1))运行时,我得到ValueError:无法将R6B字符串转换为float。c = df.filter(like ='ZONE').replace(d).astype(float).values但是,如果我用原始字典替换区域值,则它会正常运行。输入:dfHP ZONE Value ZONE1 Value13 R7A 0.7009 M1-4/R6B 0.001282 R6A 0.5842 M1-4/R7A 0.000097 M1-6/R10 0.1909 M1-4/R6A 0.735769 R6B 0.6919 PARK 0.034596 PARK 1.0400 M1-4/R6A 0.330029.3 M1-4/R6A 0.7878 PARK 0.5970010.6 M1-4/R6B 0.0291 R6A 0.2962111.9 R9 0.0084 M1-4 0.0005813.2 M1-5/R10 0.0049 M1-4 0.6556814.5 M1-4/R7A 0.0050 C5-3 0.0009615.8 M1-5/R7-3 0.0189 C5-3 1.5932717.1 M1-5/R9 0.3296 M1-4/R6B 0.4391818.4 C5-3 0.5126 R6B 0.2083519.7 M1-4 0.5126 PARK 0.22404
添加回答
举报
0/150
提交
取消