为什么获取IP地址会引发异常？

Question

背景：我的程序启动，并且必须获取正在其上运行的计算机的IP地址。它是客户端-服务器体系结构中的“服务器”，用于接收传入的tcp-ip消息。我还应该添加机器：有可用的多IP地址正在运行Windows 2008 R2 Server这是获取IP地址的代码：  public bool IsNetworkAvailable    {        get        {            return System.Net.NetworkInformation.NetworkInterface.GetIsNetworkAvailable();        }    }    public string thisIP { get; private set; }    public void GetThisIP()    {        if (!string.IsNullOrEmpty(thisIP))        {            return;        }        thisIP = "*";        if (IsNetworkAvailable)        {            using (System.Net.Sockets.Socket socket = new System.Net.Sockets.Socket(                System.Net.Sockets.AddressFamily.InterNetwork,                System.Net.Sockets.SocketType.Dgram, 0))            {                socket.Connect("11.0.1.5", 65530);                System.Net.IPEndPoint endPoint = socket.LocalEndPoint as System.Net.IPEndPoint;                thisIP = endPoint.Address.ToString();            }        }    }这是错误消息：(0x80004005): A socket operation was attempted to an unreachable network 11.0.1.5:65530 at System.Net.Sockets.Socket.Connect(IPAddress[] addresses, Int32 port)

Answer 1

我假设特定的客户端计算机比收到此错误的网络有些故障。

引用@Stephen Cleary

此错误表明网络未连接或配置不正确。这绝对是客户端计算机上的错误，而不是服务器上的错误。您无法做很多事情来“解决”问题。您几乎可以做的就是升级客户端的网络驱动程序并检查连接问题（也许它们几乎不在无线范围内，或者以太网电缆缺少其锁定选项卡）。

Answer 2

        System.Net.NetworkInformation.UnicastIPAddressInformation mostSuitableIp = null;
            var networkInterfaces = System.Net.NetworkInformation.NetworkInterface.GetAllNetworkInterfaces();
            foreach (var network in networkInterfaces)
            {
                if (network.OperationalStatus != System.Net.NetworkInformation.OperationalStatus.Up)
                {
                    continue;
                }
                var properties = network.GetIPProperties();
                if (properties.GatewayAddresses.Count == 0)
                {
                    continue;
                }
                if (mostSuitableIp != null)
                {
                    break;
                }
                foreach (var address in properties.UnicastAddresses)
                {
                    if (address.Address.AddressFamily != System.Net.Sockets.AddressFamily.InterNetwork)
                    {
                        continue;
                    }
                    if (System.Net.IPAddress.IsLoopback(address.Address))
                    {
                        continue;
                    }
                    if (mostSuitableIp == null && address.IsDnsEligible)
                    {
                        mostSuitableIp = address;
                        break;
                    }
               }
            }
            thisIP = mostSuitableIp != null ? mostSuitableIp.Address.ToString() : "";