Apache-最近一小时的日志

Question

我正在使用cPanel帐户，并具有一个Apache 2.4访问日志，该日志存储其日志，例如：66.249.93.30 - - [04/May/2018:21:26:39 +0200] "GET / HTTP/1.1" 302 207 "-" "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko; Google Page Speed Insights) Chrome/41.0.2272.118 Safari/537.36"66.249.93.30 - - [05/May/2018:10:26:39 +0200] "GET / HTTP/1.1" 302 207 "-" "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko; Google Page Speed Insights) Chrome/41.0.2272.118 Safari/537.36"该日期的格式为日期“ +％d /％B /％Y：％k：％M：％S”使用bash脚本，我只想提取最近一小时记录的行，例如：完整的日志文件：66.249.93.30 - - [04/May/2018:21:26:39 +0200] First Line66.249.93.30 - - [05/May/2018:11:00:21 +0200] Second Line66.249.93.30 - - [05/May/2018:11:15:39 +0200] Third Line66.249.93.30 - - [05/May/2018:12:00:11 +0200] Fourth Line当前时间： 05 / May / 2018：12 : 01：06日志从： 5月5日11:01-12:01之间的时间间隔开始过滤后的输出：66.249.93.30 - - [05/May/2018:11:15:39 +0200] Third Line66.249.93.30 - - [05/May/2018:12:00:11 +0200] Fourth Line我已经尝试过使用awk和其他一些建议，但是我无法使其正常工作，我们将不胜感激！

Answer 1

$ date

Sat, May 05, 2018 10:49:13 AM

$ cat tst.awk

{

    split($4,t,/[[ :\/]/)

    mthNr = sprintf("%02d",(index("JanFebMarAprMayJunJulAugSepOctNovDec",t[3])+2)/3)

    curTime = t[4] mthNr t[2] t[5] t[6] t[7]

}

curTime >= minTime

$ awk -v minTime=$(date -d '60 min ago' '+%Y%m%d%H%M%S') -f tst.awk file

66.249.93.30 - - [05/May/2018:11:00:21 +0200] Second Line

66.249.93.30 - - [05/May/2018:11:15:39 +0200] Third Line

66.249.93.30 - - [05/May/2018:12:00:11 +0200] Fourth Line

使用问题的时间来获得问题的预期输出：

$ awk -v minTime=$(date -d '2018/05/05 11:01:06' '+%Y%m%d%H%M%S') -f tst.awk file

66.249.93.30 - - [05/May/2018:11:15:39 +0200] Third Line

66.249.93.30 - - [05/May/2018:12:00:11 +0200] Fourth Line