我有一个脚本,必须执行以下操作。在插入一些数据之后,它必须显示一条消息“成功插入”。它不起作用,但是我不知道为什么我对Jquery缺乏经验。我有3个档案。脚本文件:$(document).on("click", ".btnAddSubcat", function(e) {event.preventDefault();var subcatvalue = $('.subCat').val();var subcatprocedure = $('.subProcedure').val();var url = "../service/functions/postActions.php";swal({ title: 'Add a new sub-category?', text: "Are you sure to Add this sub-category?", type: 'warning', showCancelButton: true, confirmButtonColor: '#3085d6', cancelButtonColor: '#d33', confirmButtonText: 'Yes, Add it!'}).then(function () { $.ajax({ type: 'POST', url : url, data: {'subCat': subcatvalue, 'Procedure': subcatprocedure}, success: function (data) { swal({ title: 'Add!', text: "You Add a sub-category!", type: 'success', confirmButtonColor: '#3085d6', confirmButtonText: 'OK' }).then(function () { window.location.reload(); }) } }); })}); PHP文件<div class="form-group"> <label for="inputsubcat" class="col-sm-2 control-label">SubCategory:</label> <div class="col-sm-10"> <input type="text" class="form-control subCat" name="subCat" placeholder="..."> </div> </div> <div class="form-group"> <label for="inputprocedure" class="col-sm-2 control-label">Procedure:</label> <div class="col-sm-10"> <textarea name="Procedure" rows="8" cols="30" style=" resize: none;" class="form-control subProcedure" placeholder="..."></textarea> </div> </div>功能文件function AddSubCat() {$Catid = $_POST['cat-select'];$Subnaam = $_POST['subCat'];$procedure = $_POST['Procedure'];和一些插入的东西。可以,但不会显示该消息。我感谢您的帮助!一定是这样插入后插入 之前的图像
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