需要帮忙,我期望这样的输出1.1.1.1 is server01.1.1.2 is server11.1.1.3 is server21.1.1.4 is server3但是我没有得到我期望的输出。这是我的代码IP = ['1.1.1.1', '1.1.1.2', '1.1.1.3', '1.1.1.4']for ip in IP: for i in range(len(IP)): print(ip + ' is ' + 'server'+ str(i))输出:1.1.1.1 is server01.1.1.1 is server11.1.1.1 is server21.1.1.1 is server31.1.1.2 is server01.1.1.2 is server11.1.1.2 is server21.1.1.2 is server31.1.1.3 is server01.1.1.3 is server11.1.1.3 is server21.1.1.3 is server31.1.1.4 is server01.1.1.4 is server11.1.1.4 is server21.1.1.4 is server3有人能帮我吗?
1 回答

肥皂起泡泡
TA贡献1829条经验 获得超6个赞
您不需要在这里两个循环。只需写:
for i in range(len(IP)):
print(IP[i] + ' is ' + 'server'+ str(i))
输出:
1.1.1.1 is server0
1.1.1.2 is server1
1.1.1.3 is server2
1.1.1.4 is server3
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