在python中保存和加载

Question

我已经四处搜寻，但无法找到针对我的特定问题的解决方案。我正在尝试做的是获取一个文本文件，其中文件的每一行都包含一个变量。在文本文件中一行一行health == 1099239gold == 123otherVar == 'Town'问题是我无法将它们分成不同的变量，而不仅仅是包含所有信息的一个变量。目前，我将其作为保存到文件的测试SaveFileName = input('What would you like to name your save: ')f = open(SaveFileName + '.txt','w+')health = input('Health: ')gold = input('Gold: ')otherVar = input('Other: ')otherVar = ("'" + otherVar + "'")f.write('health == ' + health +'\ngold == ' + gold + '\notherVar == ' + otherVar)print('done')f.close()print('closed')我的问题不在于保存，因为这似乎完全符合预期。这是负载SaveFileName = input('Save name to load: ')global healthglobal goldglobal otherVarhealth = 100gold = 1000otherVar = 'null'def pause():    pause = input('Press enter to continue. ')F = open(SaveFileName + '.txt')for line in F:    eval(F.readline())print(health)pause()print(gold)pause()print(otherVar)pause()运行加载文件时，它允许我输入保存文件名，然后在加载时返回此文件名Traceback (most recent call last):  File "C:/Users/Harper/Dropbox/Python programming/Test area/Load file test.py", line 12, in <module>    eval(F.readline())  File "<string>", line 0    ^SyntaxError: unexpected EOF while parsing

Answer 1

f = open('your_file_name.txt')

for line in f:

    exec(line)

基本上，您可以使用exec ask Python解释器运行每一行。

Answer 2

您可以将其放入字典中，并通过键获取值

datas = {}

with open('demo.txt') as f:

    for line in f.readlines():

        key, value = line.split('=')

        datas[key.strip()] = value.replace("'", '').strip()

print(datas)

输出

{

'name': 'John',

'health': '100',

'gold': '75',

'currentCell': 'Town'

}