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TA贡献1777条经验 获得超3个赞
Chess
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错误:list.append(“,” .join(['“%s”'f.read()。splitlines()])中行的%类型错误:描述符'append'需要一个'list'对象,但已收到'str'注销
TA贡献1876条经验 获得超7个赞
代替
for item in list: item.lower()
将变量的名称更改list
为l
或在Python中不是保留字的任何内容,并使用以下行,显然用您为列表命名的任何内容l
。
l = [item.lower() for item in l]
该lower
方法以所有小写字母返回字符串的副本。创建字符串后,没有任何内容可以修改其内容,因此您需要创建一个包含所需内容的新字符串。
TA贡献1796条经验 获得超10个赞
这是可以做到的:
In [6]: l = ['Suzuki music', 'Chinese music', 'Conservatory', 'Blue grass']
In [7]: map(str.lower, l)
Out[7]: ['suzuki music', 'chinese music', 'conservatory', 'blue grass']
您的代码无法按预期方式运行的原因之一是item.lower()不会修改字符串(在Python中,字符串是不可变的)。而是返回字符串的小写版本,然后您的代码将其忽略。
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