Python：替换字符串列表中的非ascii字符

Question

我了解关于stackoverflow的许多非ascii字符问题，但是由于我是一个新手，因此我无法成功实现它们，而且我发现整个“ unicode”概念很难理解。所以我有一个清单-mylist = ["apple", "samsung", "toshiba", "Don’t know", "Can’t recall"] 我想访问索引3和4的单引号并将其替换为撇号。我尝试了这个：# -*- coding: utf-8 -*-mylist = ["hello", "don't know", "Don’t know", "Can't recall"]for word in mylist:    word.replace(u"’", "'")print mylist我收到以下错误：UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 3: ordinal not in range(128)不知道这是否有用，但是我使用的是python 2.x版本，并且我知道如果使用的是版本3，则可能不会发生此问题。

Answer 1

>>> mylist = ["apple", "samsung", "toshiba", "Don’t know", "Can’t recall"]

>>> [item.replace('\xe2\x80\x99',"'") for item in mylist]

['apple', 'samsung', 'toshiba', "Don't know", "Can't recall"]

如果所有项目都已经是unicode了：

>>> mylist = [u"apple", u"samsung", u"toshiba", u"Don’t know", u"Can’t recall"]

>>> [item.replace(u'’',u"'") for item in mylist]

[u'apple', u'samsung', u'toshiba', u"Don't know", u"Can't recall"]