peewee和python上的通配符和搜索语法格式

Question

尝试重构collectionsQuery中的keywordAlt位def countSubject(genres):    for keyword in genres:          keywordAlt = '%'+keyword+'%'        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** keywordAlt, Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)        if collectionsQuery.count() > 5:            print keyword, collectionsQuery.count()我正在重构此代码段，并且想要首先删除keywordAlt位，并将文本包含在我的查询中。然而        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** '%'+keyword+'%', Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)但是，使用第二种方法，它可以匹配所有内容。        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** %keyword%, Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)这被解释为对“关键字”的通配符搜索正确的语法是什么？