为什么在不正确的猜测之后此功能不会重新提示用户？

Question

我一直在空闲时间写一段代码，忙于打开/关闭文件，以尝试获得100％安全的文件。到目前为止，我有：def StartLock():    my_pass = open("pass.txt",  "r+")    passcode = my_pass.read()    my_pass.close()    # Establish "passcode" variable by reading hidden text file    if passcode != "":             PasswordLock(input("Password: "))     elif passcode == "": #Passcode is empty            print("Passcode not set, please set one now.")            my_pass = open("pass.txt", "r+")            passcode  = my_pass.write(input("New Pass: ")) #User establishes new pass            my_pass.close()                            print("Passcode set to :" + passcode)            PasswordLock(passcode) #User is passed on with correct pass to the lock    def PasswordLock(x):            my_pass = open("pass.txt", "r+")            passcode = my_pass.read()            my_pass.close()            attempts = 3            def LockMech(x): #Had to do this to set attempts inside instance while not resetting the num every guess                   if attempts != 3:                           print("Attempts Left: " + str(attempts))                   if x == passcode:                           print("Passcode was correct. Opening secure files...")                           return True                   elif attempts == 0:                           print("You are out of attempts, access restricted.")                           Close()                   elif x != passcode and attempts > 0:                           print("Passcode was not corrent, please try again.") #This does get printed to console when I type in a wrong pass, so it gets here                           attempts = attempts - 1                           LockMech(input(":")) #This is what seems to be broken :(def Close():    passStartLock()出于某种原因，当我运行此命令（已经在“ pass.txt”中存储了一个单词）并有意输入错误的密码进行错误测试时，不会再次提示我输入其他密码并按原样打印我的尝试。我确保在另一个函数中定义一个函数是可以接受的，并且我的拼写是正确的，并且在尝试使代码正常工作之后，我找不到问题了。。