如何找到用<tag>…</>指定的字符的字符位置？Python

Question

我想获得的位置<，并>认为是真实的tag，当它们被嵌入在这样的事情<tag "510270">calculate</>。我有这样的句子：sentence = "After six weeks and seventeen tentative approaches the only serious tender came from Daniel. He had offered a paltry #2 a week for the one-time woodman's home, sane enough in this, at least, to <tag "510270">calculate</> safety to the nearest new penny piece. "sentence2 = "After six weeks and seventeen tentative approaches the only serious tender came from Daniel. He had offered a paltry #2 a week for the one-time woodman's < home, sane enough in this, at least, to <tag "510270">calculate</> safety to the nearest new penny > piece. "sentence3 = "After six weeks and seventeen tentative approaches the only serious tender came from Daniel. He had offered a paltry #2 a week for the one-time woodman's > home, sane enough in this, at least, to <tag "510270">calculate</> safety to the nearest new penny < piece. "我需要的cfrom和incfrom是和第一的位置第2<内的<tag "XXXX">...</>，我需要的CTO和incto是第1第2的位置和>内<tag "XXXX">...</>对于句子2和句子3之类的句子，该句子在哪里出现<或>出现在哪里，我该<tag "XXXX">...</>怎么办？对于句子1，我可以简单地做到这一点：cfrom,cto = 0,0for i,c in enumerate(sentence1):  if c == "<":    cfrom == i  breakfor i,c in enumerate(sentence1.reverse):  if c == ">":    cto == len(sentence)-i  breakincfrom incto = 0,0fromtrigger, totrigger = False, Falsefor i,c in enumerate(sentence1[cfrom:]):  if c == ">":    incfrom = cfrom+i  breakfor i,c in enumerate(sentence1[incfrom:cto]):  if c == "<":    incto = i  break

Answer 1

如果我正确理解这一点，则应该可以正常工作（假设您不更改变量i ,c）

cfrom,cto = 0,0

for i,c in enumerate(sentence1):

  if c == "<tag":

    cfrom == i 

  break

for i,c in enumerate(sentence1):

  if c == ">":

    cto == i \\going forward from cfrom

  break

incfrom incto = 0,0

fromtrigger, totrigger = False, False

for i,c in enumerate(sentence1[cto:]):\\after the tag is opened, look for the start of closing tag

  if c == "</":

    incfrom = i

  break

for i,c in enumerate(sentence1[cto:]):

  if c == ">":

    incto = i

  break