使用字符串中的整数创建具有这么多数字的字典（或列表）

Question

所以我有这个由数字和单词组成的文本（wordnet）文件，例如这样的-"09807754 18 n 03 aristocrat 0 blue_blood 0 patrician"我想读第一个数字作为其后单词的字典名称（或列表）。它的布局永远不会改变，它始终是一个8位数字的键，后跟两位数字，一个字母和两位数字。最后两位数字（03）表示与前8位数字键关联的单词数（在这种情况下为三个单词）。我的想法是我将在字符串中搜索第14位，并使用该数字运行循环以选择与该键相关的所有单词所以我认为它会像这样with open('nouns.txt','r') as f:    for line in f:        words = range(14,15)        numOfWords = int(words)            while i =< numOfWords                #here is where the problem arises,                 #i want to search for words after the spaces 3 (numOfWords) times                 #and put them into a dictionary(or list) associated with the key                range(0,7) = {word(i+1), word(i+2)}从技术上讲，我正在寻找以下任何一种更有意义：09807754 = { 'word1':aristocrat, 'word2':blue_blood , 'word3':patrician }or09807754 = ['aristocrat', 'blue_blood', 'patrician']显然，这不会运行，但是如果有人可以给我任何指示，将不胜感激

Answer 1

>>> L = "09807754 18 n 03 aristocrat 0 blue_blood 0 patrician".split()

>>> L[0], L[4::2]

('09807754', ['aristocrat', 'blue_blood', 'patrician'])

>>> D = {}

>>> D.update({L[0]: L[4::2]})

>>> D

{'09807754': ['aristocrat', 'blue_blood', 'patrician']}

对于您的注释中的额外行，需要一些额外的逻辑

>>> L = "09827177 18 n 03 aristocrat 0 blue_blood 0 patrician 0 013 @ 09646208 n 0000".split()

>>> D.update({L[0]: L[4:4 + 2 * int(L[3]):2]})

>>> D

{'09807754': ['aristocrat', 'blue_blood', 'patrician'], '09827177': ['aristocrat', 'blue_blood', 'patrician']}

Answer 2

res = {}

with open('nouns.txt','r') as f:

    for line in f:

        splited = line.split()

        res[splited[0]] = [w for w in splited[4:] if not w.isdigit()] 

输出：

{'09807754': ['aristocrat', 'blue_blood', 'patrician']}