如何在JavaScript或jQuery中过滤JSON数据？

Question

如何使用Javascript或jQuery过滤JSON数据？这是我的JSON数据：[{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"},{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},{"name":"Lenovo Thinkpad 41A424448","website":"google"},{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]JavaScript：obj1 = JSON.parse(jsondata);现在我只想要包含网站的名称和网站数据等于“ yahoo”

Answer 1

尝试这种方式，甚至可以通过其他键进行过滤

数据：

var my_data = [{"name":"Lenovo Thinkpad 41A4298","website":"google"},

{"name":"Lenovo Thinkpad 41A2222","website":"google"},

{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},

{"name":"Lenovo Thinkpad 41A424448","website":"google"},

{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},

{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},

{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},

{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}];

用法：

//We do that to ensure to get a correct JSON

var my_json = JSON.stringify(my_data)

//We can use {'name': 'Lenovo Thinkpad 41A429ff8'} as criteria too

var filtered_json = find_in_object(JSON.parse(my_json), {website: 'yahoo'});

过滤功能

function find_in_object(my_object, my_criteria){

  return my_object.filter(function(obj) {

    return Object.keys(my_criteria).every(function(c) {

      return obj[c] == my_criteria[c];

    });

  });

}