如何在不使用JQUERY的情况下联接两个JavaScript对象

Question

我有两个json对象obj1和obj2，我想将它们合并并创建一个json对象。结果json应该具有obj2中的所有值和obj2中不存在的obj1中的值。Question:var obj1 = {    "name":"manu",    "age":23,    "occupation":"SE"}var obj2 = {    "name":"manu",    "age":23,    "country":"india"}Expected:var result = {    "name":"manu",    "age":23,    "occupation":"SE",    "country":"india"}

Answer 1

使用Jquery的最简单方法-

var finalObj = $.extend(obj1, obj2);

没有Jquery-

var finalobj={};

for(var _obj in obj1) finalobj[_obj ]=obj1[_obj];

for(var _obj in obj2) finalobj[_obj ]=obj2[_obj];

Answer 2

1）

var merged = {};

for(key in obj1)

    merged[key] = obj1[key];

for(key in obj2)

    merged[key] = obj2[key];

2）

var merged = {};

Object.keys(obj1).forEach(k => merged[k] = obj1[k]);

Object.keys(obj2).forEach(k => merged[k] = obj2[k]);

要么

Object.keys(obj1)

    .concat(Object.keys(obj2))

    .forEach(k => merged[k] = k in obj2 ? obj2[k] : obj1[k]);

3）最简单的方法：

var merged = {};

Object.assign(merged, obj1, obj2);