3 回答
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TA贡献1848条经验 获得超6个赞
为了增加TJ的答案,超过最小/最大值会生成一个无效日期。
let maxDate = new Date(8640000000000000);
let minDate = new Date(-8640000000000000);
console.log(new Date(maxDate.getTime()).toString());
console.log(new Date(maxDate.getTime() - 1).toString());
console.log(new Date(maxDate.getTime() + 1).toString()); // Invalid Date
console.log(new Date(minDate.getTime()).toString());
console.log(new Date(minDate.getTime() + 1).toString());
console.log(new Date(minDate.getTime() - 1).toString()); // Invalid Date
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TA贡献1860条经验 获得超8个赞
代码更清晰但效率更低
new Date('1970-01-01Z00:00:00:000') //returns Thu Jan 01 1970 01:00:00 GMT+0100 (Central European Standard Time)
new Date('1970-01-01Z00:00:00:000').getTime() //returns 0
new Date('1970-01-01Z00:00:00:001').getTime() //returns 1
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