3 回答
TA贡献1796条经验 获得超4个赞
>>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'}
>>> 'one' in d.values()
True
出于好奇,一些比较时机:
>>> T(lambda : 'one' in d.itervalues()).repeat()
[0.28107285499572754, 0.29107213020324707, 0.27941107749938965]
>>> T(lambda : 'one' in d.values()).repeat()
[0.38303399085998535, 0.37257885932922363, 0.37096405029296875]
>>> T(lambda : 'one' in d.viewvalues()).repeat()
[0.32004380226135254, 0.31716084480285645, 0.3171098232269287]
编辑:并且,如果您想知道为什么...原因是上述每个返回的对象类型不同,它可能适合也可能不适合查找操作:
>>> type(d.viewvalues())
<type 'dict_values'>
>>> type(d.values())
<type 'list'>
>>> type(d.itervalues())
<type 'dictionary-valueiterator'>
EDIT2:根据注释中的请求...
>>> T(lambda : 'four' in d.itervalues()).repeat()
[0.41178202629089355, 0.3959040641784668, 0.3970959186553955]
>>> T(lambda : 'four' in d.values()).repeat()
[0.4631338119506836, 0.43541407585144043, 0.4359898567199707]
>>> T(lambda : 'four' in d.viewvalues()).repeat()
[0.43414998054504395, 0.4213531017303467, 0.41684913635253906]
TA贡献1864条经验 获得超6个赞
Python字典具有get(key)函数
>>> d.get(key)
例如,
>>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'}
>>> d.get('3')
'three'
>>> d.get('10')
none
如果您的密钥不存在,将返回none值。
foo = d[key] # raise error if key doesn't exist
foo = d.get(key) # return none if key doesn't exist
与小于3.0和大于5.0的版本相关的内容。。
TA贡献1895条经验 获得超3个赞
不同类型检查值是否存在
d = {"key1":"value1", "key2":"value2"}
"value10" in d.values()
>> False
如果值列表怎么办
test = {'key1': ['value4', 'value5', 'value6'], 'key2': ['value9'], 'key3': ['value6']}
"value4" in [x for v in test.values() for x in v]
>>True
如果带有字符串值的值列表怎么办
test = {'key1': ['value4', 'value5', 'value6'], 'key2': ['value9'], 'key3': ['value6'], 'key5':'value10'}
values = test.values()
"value10" in [x for v in test.values() for x in v] or 'value10' in values
>>True
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