UITapGestureRecognizer-单击和双击

Question

我正在尝试向UITapGestureRecognizers视图添加2 ，一个用于单击，一个用于双击事件。单抽头识别器正在按预期运行（单独运行）。但是我似乎无法使双击识别器正常工作。已经尝试具有类似性质的实验：cancelsTouchesInView，delaysTouchesBegan和delaysTouchesEnded，但仍然无法正常工作。当我双击时，将始终激活单击识别器，并且还将将双击事件发送到超级视图。但是自定义双击识别器似乎根本没有得到通知。文档似乎表明可以将上述3个属性用于此目的。但是我不确定应该设置哪些值以及在哪些识别器上（单，双或双）。希望有人对此有所帮助。以下是最新更新的代码块。// ****** gesture recognizers ******- (void)addSingleAndDoubleTapGestureRecognizersToView:(UIView *)view{    // single tap        UITapGestureRecognizer *singleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector(handleSingleTapOnView:)];                                     [singleTapRecognizer setNumberOfTouchesRequired:1];    [view addGestureRecognizer: singleTapRecognizer];    // double tap     UITapGestureRecognizer *doubleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector (handleDoubleTapOnView:)];            [doubleTapRecognizer setNumberOfTouchesRequired:2];             [singleTapRecognizer requireGestureRecognizerToFail: doubleTapRecognizer];    [view addGestureRecognizer: doubleTapRecognizer];         }- (void)handleSingleTapOnView:(id)sender{}- (void)handleDoubleTapOnView:(id)sender{}

Answer 1

UITapGestureRecognizer *singleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doSingleTap)] autorelease];

singleTap.numberOfTapsRequired = 1; 

[self.view addGestureRecognizer:singleTap];

UITapGestureRecognizer *doubleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doDoubleTap)] autorelease];

doubleTap.numberOfTapsRequired = 2; 

[self.view addGestureRecognizer:doubleTap];

[singleTap requireGestureRecognizerToFail:doubleTap];

注意： 如果要使用 numberOfTouchesRequired 它，必须 .numberOfTouchesRequired = 1;

对于斯威夫特

let singleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didPressPartButton))

singleTapGesture.numberOfTapsRequired = 1

view.addGestureRecognizer(singleTapGesture)

let doubleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didDoubleTap))

doubleTapGesture.numberOfTapsRequired = 2

view.addGestureRecognizer(doubleTapGesture)

singleTapGesture.require(toFail: doubleTapGesture)

Answer 2

Swift 3解决方案：

let singleTap = UITapGestureRecognizer(target: self, action:#selector(self.singleTapAction(_:)))

singleTap.numberOfTapsRequired = 1

view.addGestureRecognizer(singleTap)

let doubleTap = UITapGestureRecognizer(target: self, action:#selector(self.doubleTapAction(_:)))

doubleTap.numberOfTapsRequired = 2

view.addGestureRecognizer(doubleTap)

singleTap.require(toFail: doubleTap)

在代码行singleTap.require（toFail：doubleTap）中，我们强制单击以等待并确保tap事件不是双击。

Answer 3

// ----首先，您必须分配双击手势------- //

UITapGestureRecognizer* doubleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleDoubleTap:)];

UITapGestureRecognizer* singleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleSingleTap:)];

[singleTap requireGestureRecognizerToFail : doubleTap];

[doubleTap setDelaysTouchesBegan : YES];

[singleTap setDelaysTouchesBegan : YES];

// -----------------------抽头数---------------- //

[doubleTap setNumberOfTapsRequired : 2];

[singleTap setNumberOfTapsRequired : 1];

// -------在视图或按钮上添加双击和单击手势-------- //

[self.view addGestureRecognizer : doubleTap];

[self.view addGestureRecognizer : singleTap];