如何使用返回可变引用的迭代器创建自己的数据结构？

Question

我已经在Rust中创建了一个数据结构，我想为其创建迭代器。不变的迭代器很容易。我目前有这个，并且工作正常：// This is a mock of the "real" EdgeIndexes class as// the one in my real program is somewhat complex, but// of identical typestruct EdgeIndexes;impl Iterator for EdgeIndexes {    type Item = usize;    fn next(&mut self) -> Option<Self::Item> {        Some(0)    }    fn size_hint(&self) -> (usize, Option<usize>) {        (0, None)    }}pub struct CGraph<E> {    nodes: usize,    edges: Vec<E>,}pub struct Edges<'a, E: 'a> {    index: EdgeIndexes,    graph: &'a CGraph<E>,}impl<'a, E> Iterator for Edges<'a, E> {    type Item = &'a E;    fn next(&mut self) -> Option<Self::Item> {        match self.index.next() {            None => None,            Some(x) => Some(&self.graph.edges[x]),        }    }    fn size_hint(&self) -> (usize, Option<usize>) {        self.index.size_hint()    }}我想创建一个返回可变引用的迭代器。我已经尝试过这样做，但是找不到一种方法来编译它：pub struct MutEdges<'a, E: 'a> {    index: EdgeIndexes,    graph: &'a mut CGraph<E>,}impl<'a, E> Iterator for MutEdges<'a, E> {    type Item = &'a mut E;    fn next(&mut self) -> Option<&'a mut E> {        match self.index.next() {            None => None,            Some(x) => self.graph.edges.get_mut(x),        }    }    fn size_hint(&self) -> (usize, Option<usize>) {        self.index.size_hint()    }}编译会导致以下错误：error[E0495]: cannot infer an appropriate lifetime for lifetime parameter in function call due to conflicting requirements  --> src/lib.rs:54:24   |54 |             Some(x) => self.graph.edges.get_mut(x),   |                        ^^^^^^^^^^^^^^^^   |note: first, the lifetime cannot outlive the anonymous lifetime #1 defined on the method body at 51:5...  --> src/lib.rs:51:5   |51 | /     fn next(&mut self) -> Option<&'a mut E> {52 | |         match self.index.next() {53 | |             None => None,54 | |             Some(x) => self.graph.edges.get_mut(x),55 | |         }56 | |     }   | |_____^我不确定如何解释这些错误以及如何更改代码以允许MutEdges返回可变引用。