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使用PHP上传(二进制)图片到数据库,然后在提取出来

使用PHP上传(二进制)图片到数据库,然后在提取出来

慕仰6228704 2019-11-27 22:51:09
CREATE TABLE ccs_image ( id int(4) unsigned NOT NULL auto_increment, description varchar(250) default NULL, bin_data longblob, filename varchar(50) default NULL, filesize varchar(50) default NULL, filetype varchar(50) default NULL, PRIMARY KEY (id))engine=myisam DEFAULT charset=utf8upimage.php运行一直都是请求失败,请重试<?php header("Content-type:text/html;charset=utf8");if (isset($_POST['submit'])) {  $form_description = $_POST['form_description'];  $form_data_name = $_FILES['form_data']['name'];  $form_data_size = $_FILES['form_data']['size'];  $form_data_type = $_FILES['form_data']['type'];  $form_data = $_FILES['form_data']['tmp_name'];    $servername = "localhost";$username = "root";$password = "root";$dbname = "test";  $conn = mysqli_connect($servername, $username, $password, $dbname); if(! $conn ){    die("数据库连接失败" . mysqli_error());}else{echo '数据库连接成功!';}  /* echo "<script>alert('提示内容')</script>";*/$data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));  //echo "mysqlPicture=".$data;$sql="insert into sss values('".$data."','');";  $result = $conn->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype)         VALUES ('".$form_description."','".$data."','".$form_data_name."','".$form_data_size."','".$form_data_type."')");        if ($result) {    echo "图片已存储到数据库";  } else {    echo "请求失败,请重试";}}    ?>upimage.html<!doctype html><html><head>  <meta charset="UTF-8">  <meta name="viewport"     content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">  <meta http-equiv="X-UA-Compatible" content="ie=edge">  <style type="text/css">    *{margin: 1%}  </style>  <title>Document</title></head><body><form method="post" action="upimage.php" enctype="multipart/form-data">  描述:  <input type="text" name="form_description" size="40">  <input type="hidden" name="MAX_FILE_SIZE" value="1000000"> <br>  上传文件到数据库:  <input type="file" name="form_data" size="40"><br>  <input type="submit" name="submit" value="submit"></form></body></html>getimage.php<?php  $id =2;// $_GET['id']; 为简洁,直接将id写上了,正常应该是通过用户填入的id获取的  $dsn='mysql:dbname=test;host=localhost';  $pdo=new PDO($dsn,'root','root');  $query = "select bin_data,filetype from ccs_image where id=2";  $result = $pdo->query($query);  $result=$result->fetchAll(2);//  var_dump($result);  $data = $result[0]['bin_data'];  $type = $result[0]['filetype'];  Header( "Content-type: $type");  echo $data;  ?>有人可以给我个完整代码吗 
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