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TA贡献1780条经验 获得超3个赞
关闭:首先调用ExcelFile,然后调用该.parse方法并将表单名称传递给该方法。
>>> xl = pd.ExcelFile("dummydata.xlsx")
>>> xl.sheet_names
[u'Sheet1', u'Sheet2', u'Sheet3']
>>> df = xl.parse("Sheet1")
>>> df.head()
Tid dummy1 dummy2 dummy3 dummy4 dummy5 \
0 2006-09-01 00:00:00 0 5.894611 0.605211 3.842871 8.265307
1 2006-09-01 01:00:00 0 5.712107 0.605211 3.416617 8.301360
2 2006-09-01 02:00:00 0 5.105300 0.605211 3.090865 8.335395
3 2006-09-01 03:00:00 0 4.098209 0.605211 3.198452 8.170187
4 2006-09-01 04:00:00 0 3.338196 0.605211 2.970015 7.765058
dummy6 dummy7 dummy8 dummy9
0 0.623354 0 2.579108 2.681728
1 0.554211 0 7.210000 3.028614
2 0.567841 0 6.940000 3.644147
3 0.581470 0 6.630000 4.016155
4 0.595100 0 6.350000 3.974442
您正在做的是调用驻留在类本身而不是实例上的方法,这是可以的(尽管不是很惯用),但是如果这样做,则还需要传递工作表名称:
>>> parsed = pd.io.parsers.ExcelFile.parse(xl, "Sheet1")
>>> parsed.columns
Index([u'Tid', u'dummy1', u'dummy2', u'dummy3', u'dummy4', u'dummy5', u'dummy6', u'dummy7', u'dummy8', u'dummy9'], dtype=object)
TA贡献1786条经验 获得超11个赞
以为我应该在这里添加,如果要访问行或列以遍历它们,可以执行以下操作:
import pandas as pd
# open the file
xlsx = pd.ExcelFile(PATH\FileName.xlsx)
# get the first sheet as an object
sheet1 = xlsx.parse(0)
# get the first column as a list you can loop through
# where the is 0 in the code below change to the row or column number you want
column = sheet1.icol(0).real
# get the first row as a list you can loop through
row = sheet1.irow(0).real
编辑:
该方法icol(i)和irow(i)现在已弃用。您可以使用sheet1.iloc[:,i]获取第i sheet1.iloc[i,:]行和获取第i行。
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