我想让用户使用用户名和密码登录，并且该数据是否与数据库中的用户名匹配。当我尝试时，我没有收到任何错误，但是没有用。我在Dreamweaver中使用html和php，在phpMyAdmin中使用WAM。我将同时包括表单文档和随附的php文档：loginpage.php <?phpinclude('login.php'); // Includes Login Scriptif(isset($_SESSION['login_user'])){header("location: index.php");}?><table width="15px" border="0"><form form action='login.php' method='POST'><tr><td>Username</td><td><input type="text" name="username" /></td></tr><tr><td>Password</td><td><input type="password" name="password" /></td></tr><tr> <td><input type="submit" name="submit" value="submit"/></td></tr></form>ogin.php <html> <head> <title>Login</title> </head> <body> <?php session_start(); // Starting Session $error=''; // Variable To Store Error Message if (isset($_POST['submit'])) { if (empty($_POST['username']) || empty($_POST['password'])) { $error = "Username or Password is invalid"; } else { // Define $username and $password $username=$_POST['username']; $password=$_POST['password']; // Establishing Connection with Server by passing server_name, user_id and password as a parameter $hostname= "localhost"; $database = "boost"; $username = "root"; $password = ""; $localhost = mysqli_connect($hostname, $username, $password, $database); if(mysqli_connect_errno()) { die("Connection Failed".mysqli_error()); } // SQL query to fetch information of registerd users and finds user match. $sql = "SELECT * FROM `users`"; $query = mysqli_query($localhost,$sql); if(!$query) { die("Query Failed".mysqli_error($localhost)); } $rows = mysqli_num_rows($query); if ($rows == 1) { $_SESSION['login_user']=$username; // Initializing Session echo "You are now logged on!"; } else { $error = "Username or Password is invalid"; } mysqli_close($localhost); // Closing Connection } } ?> </body> </html>
添加回答
举报
0/150
提交
取消