为了账号安全,请及时绑定邮箱和手机立即绑定

使用PHP将相对路径转换成绝对URL

使用PHP将相对路径转换成绝对URL

PHP
Cats萌萌 2019-10-21 10:44:31
如何使用PHP将相对路径转换为绝对URL?
查看完整描述

3 回答

?
缥缈止盈

TA贡献2041条经验 获得超4个赞

function rel2abs($rel, $base)

{

    /* return if already absolute URL */

    if (parse_url($rel, PHP_URL_SCHEME) != '') return $rel;


    /* queries and anchors */

    if ($rel[0]=='#' || $rel[0]=='?') return $base.$rel;


    /* parse base URL and convert to local variables:

       $scheme, $host, $path */

    extract(parse_url($base));


    /* remove non-directory element from path */

    $path = preg_replace('#/[^/]*$#', '', $path);


    /* destroy path if relative url points to root */

    if ($rel[0] == '/') $path = '';


    /* dirty absolute URL */

    $abs = "$host$path/$rel";


    /* replace '//' or '/./' or '/foo/../' with '/' */

    $re = array('#(/\.?/)#', '#/(?!\.\.)[^/]+/\.\./#');

    for($n=1; $n>0; $abs=preg_replace($re, '/', $abs, -1, $n)) {}


    /* absolute URL is ready! */

    return $scheme.'://'.$abs;

}


查看完整回答
反对 回复 2019-10-21
?
拉丁的传说

TA贡献1789条经验 获得超8个赞

我喜欢jordanstephens从链接提供的代码!我投它。l0oky启发了我,以确保该功能的端口,用户名和密码的网址兼容。我的项目需要它。


function rel2abs( $rel, $base )

{

    /* return if already absolute URL */

    if( parse_url($rel, PHP_URL_SCHEME) != '' )

        return( $rel );


    /* queries and anchors */

    if( $rel[0]=='#' || $rel[0]=='?' )

        return( $base.$rel );


    /* parse base URL and convert to local variables:

       $scheme, $host, $path */

    extract( parse_url($base) );


    /* remove non-directory element from path */

    $path = preg_replace( '#/[^/]*$#', '', $path );


    /* destroy path if relative url points to root */

    if( $rel[0] == '/' )

        $path = '';


    /* dirty absolute URL */

    $abs = '';


    /* do we have a user in our URL? */

    if( isset($user) )

    {

        $abs.= $user;


        /* password too? */

        if( isset($pass) )

            $abs.= ':'.$pass;


        $abs.= '@';

    }


    $abs.= $host;


    /* did somebody sneak in a port? */

    if( isset($port) )

        $abs.= ':'.$port;


    $abs.=$path.'/'.$rel;


    /* replace '//' or '/./' or '/foo/../' with '/' */

    $re = array('#(/\.?/)#', '#/(?!\.\.)[^/]+/\.\./#');

    for( $n=1; $n>0; $abs=preg_replace( $re, '/', $abs, -1, $n ) ) {}


    /* absolute URL is ready! */

    return( $scheme.'://'.$abs );

}


查看完整回答
反对 回复 2019-10-21
?
海绵宝宝撒

TA贡献1809条经验 获得超8个赞

添加了对保留当前查询的支持。对?page = 1很有帮助,依此类推...


function rel2abs($rel, $base)

{

    /* return if already absolute URL */

    if (parse_url($rel, PHP_URL_SCHEME) != '')

        return ($rel);


    /* queries and anchors */

    if ($rel[0] == '#' || $rel[0] == '?')

        return ($base . $rel);


    /* parse base URL and convert to local variables: $scheme, $host, $path, $query, $port, $user, $pass */

    extract(parse_url($base));


    /* remove non-directory element from path */

    $path = preg_replace('#/[^/]*$#', '', $path);


    /* destroy path if relative url points to root */

    if ($rel[0] == '/')

        $path = '';


    /* dirty absolute URL */

    $abs = '';


    /* do we have a user in our URL? */

    if (isset($user)) {

        $abs .= $user;


        /* password too? */

        if (isset($pass))

            $abs .= ':' . $pass;


        $abs .= '@';

    }


    $abs .= $host;


    /* did somebody sneak in a port? */

    if (isset($port))

        $abs .= ':' . $port;


    $abs .= $path . '/' . $rel . (isset($query) ? '?' . $query : '');


    /* replace '//' or '/./' or '/foo/../' with '/' */

    $re = ['#(/\.?/)#', '#/(?!\.\.)[^/]+/\.\./#'];

    for ($n = 1; $n > 0; $abs = preg_replace($re, '/', $abs, -1, $n)) {

    }


    /* absolute URL is ready! */


    return ($scheme . '://' . $abs);

}


查看完整回答
反对 回复 2019-10-21
  • 3 回答
  • 0 关注
  • 807 浏览

添加回答

举报

0/150
提交
取消
意见反馈 帮助中心 APP下载
官方微信