使用Java按钮在浏览器中打开链接？

Question

我如何在默认浏览器中单击按钮以打开以下链接：button.addActionListener(new ActionListener() {    public void actionPerformed(ActionEvent e) {        open("www.google.com"); // just what is the 'open' method?    }});？

Answer 1

使用Desktop＃browse（URI）方法。它将在用户的默认浏览器中打开一个URI。

public static boolean openWebpage(URI uri) {

    Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;

    if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {

        try {

            desktop.browse(uri);

            return true;

        } catch (Exception e) {

            e.printStackTrace();

        }

    }

    return false;

}

public static boolean openWebpage(URL url) {

    try {

        return openWebpage(url.toURI());

    } catch (URISyntaxException e) {

        e.printStackTrace();

    }

    return false;

}

Answer 2

public static void openWebpage(String urlString) {

    try {

        Desktop.getDesktop().browse(new URL(urlString).toURI());

    } catch (Exception e) {

        e.printStackTrace();

    }

}