3 回答
TA贡献1821条经验 获得超4个赞
我的解决方案与Teoman Shipahi自2015年8月以来的出色回答相同。
我有一个Web服务,该服务返回一组JSON数据,但是实际的列可能会随时间变化。
我想做的是在jqGrid中隐藏一些JSON列,并根据此特定JSON字段是否为重要字段之一(在本例中为SegmentName)来设置某些列的宽度。
这是我想出的:
$(function () {
// Load the JSON data we'll need to populate our jqGrid
// ID of a [Segment_Set] record in our database (which our web service will load the data for.
var SegmentSetId = 12345;
$.ajax(
{
type: "GET",
url: "/Service1.svc/LoadSegmentAttributes/" + SegmentSetId,
dataType: "json",
success: function (JSONdata) {
//
// Work through our JSON data, and create the two arrays needed by jqGrid
// to display this dynamic data.
//
var listOfColumnModels = [];
var listOfColumnNames = [];
for (var prop in JSONdata[0]) {
if (JSONdata[0].hasOwnProperty(prop)) {
// We have found one property (field) in our JSON data.
// Add a column to the list of Columns which we want our jqGrid to display
listOfColumnNames.push(prop);
// How do we want this field to be displayed in our jqGrid ?
var bHidden = (prop == "SegmentID") || (prop == "SegmentSequenceInx");
var columnWidth = (prop == "SegmentName") ? 200 : 50;
listOfColumnModels.push({
name: prop,
width: columnWidth,
sortable: true,
hidden: bHidden
});
}
}
// Now we have our JSON data, and list of Column Headings and Models, we can create our jqGrid.
CreateJQGrid(JSONdata, listOfColumnModels, listOfColumnNames);
}
});
});
这是创建jqGrid的函数:
function CreateJQGrid(JSONdata, listOfColumnModels, listOfColumnNames) {
// After loading the JSON data from our webservice, and establishing the list of
// Column Names & Models, we can call this function to create the jqGrid.
$("#SegmentRulesGrid").jqGrid({
datatype: "local",
data: JSONdata,
localReader: {
id: "SegmentID", // The Primary Key field in our JSONdata
repeatitems: false
},
mtype: "GET",
colNames: listOfColumnNames,
colModel: listOfColumnModels,
rowNum: 15,
loadonce: true,
gridview: true,
autowidth: true,
height: 350,
pager: '#pager',
rowList: [15, 30, 100, 300],
rownumbers: true,
viewrecords: true,
caption: 'Segment Rules',
});
}
希望这可以帮助。
显然,我的解决方案的一个缺点是,它坚持要求您在将所有 JSON数据显示在网格中之前先加载所有 JSON数据,而不是一次仅加载一页数据。如果您有大量数据,这可能是个问题。
TA贡献1785条经验 获得超8个赞
另一个解决方案;
$("#datagrid").jqGrid({
//url: "user.json",
//datatype: "json",
datatype: "local",
data: dataArray,
colNames:getColNames(dataArray[0]),
colModel:getColModels(dataArray[0]),
rowNum:100,
loadonce: true,
pager: '#navGrid',
sortname: 'SongId',
sortorder: "asc",
height: "auto", //210,
width:"auto",
viewrecords: true,
caption:"JQ GRID"
});
function getColNames(data) {
var keys = [];
for(var key in data) {
if (data.hasOwnProperty(key)) {
keys.push(key);
}
}
return keys;
}
function getColModels(data) {
var colNames= getColNames(data);
var colModelsArray = [];
for (var i = 0; i < colNames.length; i++) {
var str;
if (i === 0) {
str = {
name: colNames[i],
index:colNames[i],
key:true,
editable:true
};
} else {
str = {
name: colNames[i],
index:colNames[i],
editable:true
};
}
colModelsArray.push(str);
}
return colModelsArray;
}
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