请问在python中如何让'[1,2,3,6~10]'返回[1,2,3,6,7,8,9,10]列表？求大佬指点！

Question

请问在python中如何让'[1,2,3,6~10]'返回[1,2,3,6,7,8,9,10]列表？谢谢

Answer 1

deff(s):
parts=s[1:-1].split(',')
l=[]
forpartinparts:
ranges=part.split('~')
iflen(ranges)==1:
l.append(int(ranges[0]))
else:
foriinrange(int(ranges[0]),int(ranges[1])+1):
l.append(i)
returnl
if__name__=='__main__':
print(f('[1,2,3,6~10]'))
                            

Answer 2

fromfunctoolsimportreduce
sampleListStr='[1,2,3,6~10]'sampleList=sampleListStr.strip('[]').split(',')result=list(reduce(lambdax,y:x+y,[[int(element)]if'~'notinelementelselist(reduce(lambdax,y:range(x,y+1),[int(element1)forelement1inelement.split('~')]))forelementinsampleList]))