Android-创建JSON数组和JSON对象

Question

如何在Android中以这种格式创建JSON：由于我将传递的API将解析JsonArray，然后解析该对象。还是只传递一个json对象就可以了吗？因为我将只需要为每个服务调用插入1个事务。{    "student": [        {            "id": 1,            "name": "John Doe",            "year": "1st",            "curriculum": "Arts",            "birthday": 3/3/1995        },        {            "id": 2,            "name": "Michael West",            "year": "2nd",            "curriculum": "Economic",            "birthday": 4/4/1994        }    ]}我所知道的只是JSONObject。像这个。JSONObject obj = new JSONObject();try {    obj.put("id", "3");    obj.put("name", "NAME OF STUDENT");    obj.put("year", "3rd");    obj.put("curriculum", "Arts");    obj.put("birthday", "5/5/1993");} catch (JSONException e) {    // TODO Auto-generated catch block    e.printStackTrace();}有任何想法吗。谢谢

Answer 1

使用以下代码：

JSONObject student1 = new JSONObject();

try {

    student1.put("id", "3");

    student1.put("name", "NAME OF STUDENT");

    student1.put("year", "3rd");

    student1.put("curriculum", "Arts");

    student1.put("birthday", "5/5/1993");

} catch (JSONException e) {

    // TODO Auto-generated catch block

    e.printStackTrace();

}

JSONObject student2 = new JSONObject();

try {

    student2.put("id", "2");

    student2.put("name", "NAME OF STUDENT2");

    student2.put("year", "4rd");

    student2.put("curriculum", "scicence");

    student2.put("birthday", "5/5/1993");

} catch (JSONException e) {

    // TODO Auto-generated catch block

    e.printStackTrace();

}

JSONArray jsonArray = new JSONArray();

jsonArray.put(student1);

jsonArray.put(student2);

JSONObject studentsObj = new JSONObject();

    studentsObj.put("Students", jsonArray);

String jsonStr = studentsObj.toString();

    System.out.println("jsonString: "+jsonStr);

Answer 2

public JSONObject makJsonObject(int id[], String name[], String year[],

            String curriculum[], String birthday[], int numberof_students)

            throws JSONException {

        JSONObject obj = null;

        JSONArray jsonArray = new JSONArray();

        for (int i = 0; i < numberof_students; i++) {

            obj = new JSONObject();

            try {

                obj.put("id", id[i]);

                obj.put("name", name[i]);

                obj.put("year", year[i]);

                obj.put("curriculum", curriculum[i]);

                obj.put("birthday", birthday[i]);

            } catch (JSONException e) {

                // TODO Auto-generated catch block

                e.printStackTrace();

            }

            jsonArray.put(obj);

        }

        JSONObject finalobject = new JSONObject();

        finalobject.put("student", jsonArray);

        return finalobject;

    }

Answer 3

 JSONObject obj = new JSONObject();

            try {

                obj.put("id", "3");

                obj.put("name", "NAME OF STUDENT");

                obj.put("year", "3rd");

                obj.put("curriculum", "Arts");

                obj.put("birthday", "5/5/1993");

            } catch (JSONException e) {

                // TODO Auto-generated catch block

                e.printStackTrace();

            }

             JSONArray js=new JSONArray(obj.toString());

             JSONObject obj2 = new JSONObject();

             obj2.put("student", js.toString());