大佬们遇到过这个问题吗？js 如何筛选ID相同跟不相同得跪求！

Question

就是拿一组ID跟另一个数组做比较如果有相同得放到相同得新数组里有不相同的放到不相同数组中

Answer 1

[...arr1,...arr2].reduce((result,v)=>{
letindex=result.diff.indexOf(v)
if(index!==-1){
result.same.push(result.diff.splice(index,1)[0]);
}else{
result.diff.push(v);
}
returnresult;
},{same:[],diff:[]})
                            

Answer 2

consta=[1,2,3,4];
constb=[2,3,5,6];
functionfilterArr(arr1,arr2,type){
letdiffArr=[];
letsameArr=[];
sameArr=arr1.filter(v=>{
returnarr2.some(a=>{
returnv==a
})
})
letmergeArr=[...arr1,...arr2];
diffArr=mergeArr.filter(v=>{
return!sameArr.includes(v)
})
if(type=='same'){
returnsameArr
}else{
returndiffArr
}
}
console.log(filterArr(a,b,'same'))//[2,3]
console.log(filterArr(a,b,'diff'))//[1,4,5,6]