使用纬度经度计算两点之间的距离？

Question

这是我的尝试，它只是我的代码片段：final double RADIUS = 6371.01;double temp = Math.cos(Math.toRadians(latA))            * Math.cos(Math.toRadians(latB))            * Math.cos(Math.toRadians((latB) - (latA)))            + Math.sin(Math.toRadians(latA))            * Math.sin(Math.toRadians(latB));    return temp * RADIUS * Math.PI / 180;我使用这个公式来获得经度和经度：x = Deg + (Min + Sec / 60) / 60)

Answer 1

以上Dommer给出的Java代码给出了稍微不正确的结果，但如果您正在处理GPS轨道，则会出现小错误。以下是Java中Haversine方法的实现，它还考虑了两点之间的高度差异。

/**

 * Calculate distance between two points in latitude and longitude taking

 * into account height difference. If you are not interested in height

 * difference pass 0.0. Uses Haversine method as its base.

 * 

 * lat1, lon1 Start point lat2, lon2 End point el1 Start altitude in meters

 * el2 End altitude in meters

 * @returns Distance in Meters

 */

public static double distance(double lat1, double lat2, double lon1,

        double lon2, double el1, double el2) {

    final int R = 6371; // Radius of the earth

    double latDistance = Math.toRadians(lat2 - lat1);

    double lonDistance = Math.toRadians(lon2 - lon1);

    double a = Math.sin(latDistance / 2) * Math.sin(latDistance / 2)

            + Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2))

            * Math.sin(lonDistance / 2) * Math.sin(lonDistance / 2);

    double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));

    double distance = R * c * 1000; // convert to meters

    double height = el1 - el2;

    distance = Math.pow(distance, 2) + Math.pow(height, 2);

    return Math.sqrt(distance);

}